Expandindo `9999999` em potências de `12`
`(9999999)_{10} =`
`=3\cdot 12^{6} + 4\cdot 12^{5} + 2\cdot 12^{4} + 3\cdot 12^{3} + 0\cdot 12^{2} + 5\cdot 12^{1} + 3\cdot 12^{0}`
`= (\text{3423053})_{12}`
VALORES:
A | B |
10 | 11 |
`(9999999)_{10} =`
`=3\cdot 12^{6} + 4\cdot 12^{5} + 2\cdot 12^{4} + 3\cdot 12^{3} + 0\cdot 12^{2} + 5\cdot 12^{1} + 3\cdot 12^{0}`
`= (\text{3423053})_{12}`
VALORES:
A | B |
10 | 11 |