Expandindo `398509229` em potências de `12`
`(398509229)_{10} =`
`=B\cdot 12^{7} + 1\cdot 12^{6} + 5\cdot 12^{5} + 6\cdot 12^{4} + 2\cdot 12^{3} + 9\cdot 12^{2} + 2\cdot 12^{1} + 5\cdot 12^{0}`
`= (\text{B1562925})_{12}`
VALORES:
A | B |
10 | 11 |
`(398509229)_{10} =`
`=B\cdot 12^{7} + 1\cdot 12^{6} + 5\cdot 12^{5} + 6\cdot 12^{4} + 2\cdot 12^{3} + 9\cdot 12^{2} + 2\cdot 12^{1} + 5\cdot 12^{0}`
`= (\text{B1562925})_{12}`
VALORES:
A | B |
10 | 11 |