Expandindo `374140049` em potências de `12`
`(374140049)_{10} =`
`=A\cdot 12^{7} + 5\cdot 12^{6} + 3\cdot 12^{5} + 7\cdot 12^{4} + 0\cdot 12^{3} + 2\cdot 12^{2} + 9\cdot 12^{1} + 5\cdot 12^{0}`
`= (\text{A5370295})_{12}`
VALORES:
A | B |
10 | 11 |
`(374140049)_{10} =`
`=A\cdot 12^{7} + 5\cdot 12^{6} + 3\cdot 12^{5} + 7\cdot 12^{4} + 0\cdot 12^{3} + 2\cdot 12^{2} + 9\cdot 12^{1} + 5\cdot 12^{0}`
`= (\text{A5370295})_{12}`
VALORES:
A | B |
10 | 11 |