Expandindo `3415` em potências de `13`
`(3415)_{10} =`
`=1\cdot 13^{3} + 7\cdot 13^{2} + 2\cdot 13^{1} + 9\cdot 13^{0}`
`= (\text{1729})_{13}`
VALORES:
| A | B | C |
| 10 | 11 | 12 |
`(3415)_{10} =`
`=1\cdot 13^{3} + 7\cdot 13^{2} + 2\cdot 13^{1} + 9\cdot 13^{0}`
`= (\text{1729})_{13}`
VALORES:
| A | B | C |
| 10 | 11 | 12 |