Expandindo `2549` em potências de `13`
`(2549)_{10} =`
`=1\cdot 13^{3} + 2\cdot 13^{2} + 1\cdot 13^{1} + 1\cdot 13^{0}`
`= (\text{1211})_{13}`
VALORES:
A | B | C |
10 | 11 | 12 |
`(2549)_{10} =`
`=1\cdot 13^{3} + 2\cdot 13^{2} + 1\cdot 13^{1} + 1\cdot 13^{0}`
`= (\text{1211})_{13}`
VALORES:
A | B | C |
10 | 11 | 12 |