Expandindo `251491185` em potências de `13`
`(251491185)_{10} =`
`=4\cdot 13^{7} + 0\cdot 13^{6} + 1\cdot 13^{5} + 4\cdot 13^{4} + 5\cdot 13^{3} + 3\cdot 13^{2} + 6\cdot 13^{1} + A\cdot 13^{0}`
`= (\text{4014536A})_{13}`
VALORES:
| A | B | C |
| 10 | 11 | 12 |
`(251491185)_{10} =`
`=4\cdot 13^{7} + 0\cdot 13^{6} + 1\cdot 13^{5} + 4\cdot 13^{4} + 5\cdot 13^{3} + 3\cdot 13^{2} + 6\cdot 13^{1} + A\cdot 13^{0}`
`= (\text{4014536A})_{13}`
VALORES:
| A | B | C |
| 10 | 11 | 12 |