Expandindo `224164426` em potências de `12`
`(224164426)_{10} =`
`=6\cdot 12^{7} + 3\cdot 12^{6} + 0\cdot 12^{5} + A\cdot 12^{4} + 4\cdot 12^{3} + 9\cdot 12^{2} + 4\cdot 12^{1} + A\cdot 12^{0}`
`= (\text{630A494A})_{12}`
VALORES:
A | B |
10 | 11 |
`(224164426)_{10} =`
`=6\cdot 12^{7} + 3\cdot 12^{6} + 0\cdot 12^{5} + A\cdot 12^{4} + 4\cdot 12^{3} + 9\cdot 12^{2} + 4\cdot 12^{1} + A\cdot 12^{0}`
`= (\text{630A494A})_{12}`
VALORES:
A | B |
10 | 11 |